(-x^2+10x+36)/2=0

Solution for (-x^2+10x+36)/2=0 equation:

(-x^2+10x+36)/2=0

We multiply all the terms by the denominator


(-x^2+10x+36)=0

We get rid of parentheses

-x^2+10x+36=0

We add all the numbers together, and all the variables

-1x^2+10x+36=0

a = -1; b = 10; c = +36;
Δ = b2-4ac
Δ = 102-4·(-1)·36
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{61}}{2*-1}=\frac{-10-2\sqrt{61}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{61}}{2*-1}=\frac{-10+2\sqrt{61}}{-2}
$